I am beginner of python and trying to insert percentage sign in the output. Below is the code that I've got.
print('accuracy :', accuracy_score(y_true, y_pred)*100)
when I run this code I got 50.0001 and I would like to have %sign at the end of the number so I tried to do as below
print('Macro average precision :', precision_score(y_true, y_pred, average='macro')*100"%\n")
I got error say SyntaxError: invalid syntax
Can any one help with this?
Thank you!
Use f strings:
print(f"Macro average precision : {precision_score(y_true, y_pred, average='macro')*100}%\n")
Or convert the value to string, and add (concatenate) the strings:
print('Macro average precision : ' + str(precision_score(y_true, y_pred, average='macro')*100) + "%\n")
See the discussion here of the merits of each; basically the first is more convenient; and the second is computationally faster, and perhaps more simple to understand.
You can try this:
print('accuracy: {:.2f}%'.format(100*accuracy_score(y_true, y_pred)))
The simple, "low-tech" way is to correct your (lack of) output expression. Convert the float to a string and concatenate. To make it easy to follow:
pct = precision_score(y_true, y_pred, average='macro')*100
print('Macro average precision : ' + str(pct) + "%\n")
This is inelegant, but easy to follow.
One of the ways to go about fixing this is by using string concatenation. You can add the percent symbol to your output from your function using a simple + operator. However, the output of your function needs to be cast to a string data type in order to be able to concatenate it with a string. To cast something to a string, use str()
So the correct way to fix your print statement using this explanation would be:
print('Macro average precision : ' + str(precision_score(y_true, y_pred, average='macro')*100) + "%\n")
'Macro average precision : {:.0%}\n'.format(precision_score(y_true, y_pred, average='macro'))print(50.001"%\n").