Unable to Handle SocketException

Question

I've internet turned off my phone to trigger a SocketException error. I make my api call and at the top of the stack the error can be seen on my debugger just before the await call. I want to handle this error at the UI layer. And at the bottom of my call stack I see the method getData . My understanding is: I can wrap this in a try/catch and handle the exception. But I can't seem to grab the error.. Here is the method:

Future<String> getData(String query) async {
    try {
      List<Suburb> suburbs = await model.getSuburbs('au', query);

      if (suburbs.length == 1) {
        suburbCode = suburbs[0].code;
        isButtonDisabled = false;
        return suburbs[0].name;
      }
      return showDialog<String>(
          barrierDismissible: false,
          context: context,
          builder: (context) => SimpleDialog(
                backgroundColor: Colors.black,
                title: Text('Please choose your Suburb:'),
                children: suburbs
                    .map((suburb) => SimpleDialogOption(
                        child: Text(suburb.name),
                        onPressed: () {
                          suburbCode = suburb.code;
                          isButtonDisabled = false;

                          Navigator.of(context).pop(suburb.name);
                        }))
                    .toList(),
              ));
    } on SocketException catch (e) {
      print(e);
    }
  }

The line List<Suburb> suburbs = await model.getSuburbs('au', query); is where I make the api call and where the debugger points to. But I can't seem to 'get in to the catch block'

on SocketException catch (e) { should work. Try to add this block within getSuburbs() and check. In one of my code, I catch socket exception where the API call is made [so inside getSuburbs()] in your context) and throw a generic exception (via enum) from the caller [i.e.getData()] — Sukhi
– Sukhi, Commented Apr 17, 2020 at 13:20
maybe I should add that the method is a future for a FutureBuilder. But I don't think that makes any difference — flutter
– flutter, Commented Apr 17, 2020 at 13:58
Cool. Let me add it as an answer so that others would be benefitted as well. — Sukhi
– Sukhi, Commented Apr 17, 2020 at 14:15

Sukhi · Accepted Answer · 2020-04-17 14:16:45Z

1

The try-catch block will need at the Http post/get call as well. So, just catch the socket exception in getSuburbs(), do the needful and throw a general exception from there, if required. Something like below would work :

Future<string> getSuburbs(string country, string query){
    try {
        http.Response response =
            await http.post(.........
      } on SocketException catch (e) {
        print(e);
        throw Error.noNetworkConnection;
      } catch (e) {
        print(e);
        throw Error.unknown;
      }
}

answered Apr 17, 2020 at 14:16

Sukhi

14.4k7 gold badges40 silver badges55 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Unable to Handle SocketException

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related