Parsing unquoted JSON keys using org.json.simple in Java

Question

I have a JSON stored in a string.

String data = "{code: '0', distCode: '123'}";

I need to get the values of code, distCode. But when I try to parse it as below

JSONParser parser = new JSONParser();
JSONObject Details = (JSONObject) parser.parse(data);

Unexpected character (c) at position 2 exception is thrown.

I am sure it is because of unquoted keys in the string. How to parse the string into an JSON object using org.json.simple library?

Make it look like this "{\"code\":\"'0\", \"distCode\": \"123\"}" — Radu Mirea
– Radu Mirea, Commented Apr 18, 2020 at 7:43
I don't think you can; it's not valid JSON. You might be able to do something tricky like using an embedded JavaScript engine to evaluate it as a JavaScript object. — chrylis -cautiouslyoptimistic-
– chrylis -cautiouslyoptimistic-, Commented Apr 18, 2020 at 8:20

gokul · Accepted Answer · 2020-05-14 06:04:43Z

0

Could not find way to achieve it using org.json.simple library. Finally done it using jackson libraries.

    String data = "{code: '0', distCode: '123'}";
    ObjectMapper mapper = new ObjectMapper();
    mapper.configure(JsonParser.Feature.ALLOW_SINGLE_QUOTES, true);                               
    mapper.configure(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
    Map<String, String> Shop_Details = mapper.readValue(data), Map.class);

answered May 14, 2020 at 6:04

gokul

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