Write lambda function as def:-function

Question

I'm trying to write a lambda-function into a def:-function in order to better understand what is going on in a Python example-script I got. In some function in that script a lambda-function is integrated and I'm wondering what it would look like as def:-statement. (I'm new to using lamda functions) So here is the code:

import numpy as np
import pandas as pd

df = pd.DataFrame({"A": [18,28,29,32,35,36,37,37,39,40,42,42,46,48,54,56,57,61,61,62,63,65],                  "B":  [9,13,17,15,23,21,24,28,26,30,29,36,38,42,40,48,40,51,54,50,51,57]})

a = lambda df: np.corrcoef(df[:,0], df[:,1])[0,1]
print(a)

>>>function <lambda> at 0x0000016896784950> #result of print-statement

def lamb(df):
    g = np.corrcoef(df.iloc[:,0],df.iloc[:,1])[0,1]
    return g

b = lamb(df)
print(b)

>>>0.974499725153725 #result of print-statement

How do I alter the def lamb(df):-code so that its print-statement has the same output as the print-statement of the lambda-function?

You are not printing the same, in one your are printing a lambda function object and in the the other the result of a function call — Dani Mesejo
– Dani Mesejo, Commented Apr 18, 2020 at 17:53
I know, that's my question. How do I alter the 'def lamb(df):'-function in order that it prints the same.. — Matthi9000
– Matthi9000, Commented Apr 18, 2020 at 17:55
Just: print(a(df)) in the same way you had print(lamb(df)). Both a and lamb are functions. — DarrylG
– DarrylG, Commented Apr 18, 2020 at 17:57
print(a(df)) gives: TypeError: '(slice(None, None, None), 0)' is an invalid key — Matthi9000
– Matthi9000, Commented Apr 18, 2020 at 17:59

Praveen · Accepted Answer · 2020-04-18 17:58:08Z

2

print(a) prints a function, but

b = lamb(df)         
print(b)

print the output of the function

Try print(lamb) to get the similar result

answered Apr 18, 2020 at 17:58

Praveen

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1 Comment

Matthi9000 Over a year ago

Jep, that's it! Damn.

RMPR · Accepted Answer · 2020-04-18 17:59:20Z

1

With

print(a)

You're trying to print a function, to have the same usable output:

print(a(df))

Is what you're looking for

answered Apr 18, 2020 at 17:59

RMPR

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2 Comments

Matthi9000 Over a year ago

print(a(df)) gives: TypeError: '(slice(None, None, None), 0)' is an invalid key

RMPR Over a year ago

Can be a conflict in naming, what happens when you change either the variable name or the parameter in your lambda declaration?

Pankaj Mishra · Accepted Answer · 2020-04-18 19:36:53Z

0

just print the function lamb. this will print the function at location at 0x......

print(lamb)

answered Apr 18, 2020 at 19:36

Pankaj Mishra

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