ruby - delete from a string

Question

I have the following strings:

src = "dav://w.lvh.me:3000/Home/Transit/file"
host = "w.lvh.me:3000"

What I want to obtain is "/Home/Transit/file" using those two strings

I thought of searching for host in src and delete it the first time it appears, and everything before it, but I'm not sure exactly how to do that. Or maybe there's a better way?

Any help would be appreciated!

Victor Deryagin · Accepted Answer · 2011-05-26 14:21:14Z

8

There is a better way indeed:

require 'uri'
src = "dav://w.lvh.me:3000/Home/Transit/file"
src = URI.parse src

src.path      # => "/Home/Transit/file"

When there are spaces in the string, you must pass extra step of escaping/unescaping. Fortunantly, this is simple:

require 'uri'
src = "dav://w.lvh.me:3000/Home/Transit/Folder 144/webdav_put_request"
src = URI.parse(URL.escape src)

URL.unescape(src.path)      # => "/Home/Transit/Folder 144/webdav_put_request"

edited May 26, 2011 at 14:21

answered May 26, 2011 at 12:30

Victor Deryagin

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3 Comments

user229044 Over a year ago

Perfect answer. Not everything should be boiled down to a regular expression. You want a URI parser for parsing URIs, not yet another busted regular expression.

Andrei S Over a year ago

i forgot to ask, what if there are spaces in src ? URI.parse raises an error for example if src = "dav://w.lvh.me:3000/Home/Transit/Folder 144/webdav_put_request"

Andrei S Over a year ago

Thank you. I tried escaping with a custom function but I think it did not escape right. URI.escape works ok!

Chowlett · Accepted Answer · 2011-05-26 12:28:18Z

2

This should do the job:

src = "dav://w.lvh.me:3000/Home/Transit/file"
host = "w.lvh.me:3000"
result = src.sub(/.*#{host}/, '')
#=> "/Home/Transit/file"

answered May 26, 2011 at 12:28

Chowlett

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