Is there a more efficient way to do this - Python For Loop Strings

Question

I need to rearrange a string with this sequence: 2,4,6 ... 1, 3, 5 For example 'Hello Joe' would become 'el oHloJ' This is my code:

def encrypt(message):
    newMessage = []
    for i in range(1, len(message), 2):
        newMessage.append(message[i])
    for i in range(0,len(message),2):
        newMessage.append(message[i])

    print(newMessage)

encrypt("Hello Jo")

I was wondering if there was a more efficient way to do this? Thanks.

What should happen if the given string has an uneven number of characters? — Hampus Larsson
– Hampus Larsson, Commented Apr 24, 2020 at 10:55

Taohidul Islam · Accepted Answer · 2020-04-24 11:03:27Z

2

You can try the indexing feature, like :

def encrypt(message):
    new_message = message[1::2] + message[0::2]
    print(new_message)

encrypt("Hello Jo")

answered Apr 24, 2020 at 11:03

Taohidul Islam

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1 Comment

Hampus Larsson Over a year ago

He is basically doing the same thing you are doing with the range command. 'abc'[::2] for example, will return 'ac'. The third parameter when using indexing (just as range) is the "step" of the iterator. So when he say [1::2] He's saying: Start at index 1, go to the end of the string, and use a step-distance of 2.

Kunal Sawant · Accepted Answer · 2020-04-24 11:00:15Z

1

you can use string built-in indexing features like this I hope this is what you are trying to achieve.

   In [2]: a ="Hello Jo"

    In [5]: a[1::2] + a[0::2]
    Out[5]: 'el oHloJ'

Hope it helps

first param in[::] is from where to start where as last param in which next item to take.

answered Apr 24, 2020 at 11:00

Kunal Sawant

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