Remove all elements which is duplicated in another array in ES6 syntax

Question

var arr1= ['test', 'test1', 'test2', 'test3'];

var arr2= ['test', 'test1'];

expected output ['test2','test3'] I am able to achieve this in the browser console using -

arr1.filter(x => !arr2.includes(x));

But the problem is that "includes" seems to be not supporting in ES6.

Is there an alternative? Thanks!

Yeah, but it always merges from both arrays. I need content only from arr1 but removing entries which is present in arr2. — Sallu
– Sallu, Commented Apr 29, 2020 at 15:24
It gives me this error TS2339: Property 'includes' does not exist on type 'string[]' when I try generating bundle in react. After searching for fix I read that ES6 does not support this. — Sallu
– Sallu, Commented Apr 29, 2020 at 15:25

Sallu · Accepted Answer · 2020-04-29 15:32:24Z

1

Try this as an alternative:

const res= arr1.filter(x => arr2.indexOf(x.toString()) === -1)

Sallu

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answered Apr 29, 2020 at 15:22

Hadi Samadzad

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1 Comment

indexOf was expecting string but x was of the type {}

Srijan · Accepted Answer · 2020-04-29 15:28:08Z

1

You can try.

var arr3 = arr1.filter(x => arr2.indexOf(x)<0);

answered Apr 29, 2020 at 15:28

Srijan

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