Python project organization from sub-directories

Question

I have a number of scripts with logical groups.

.
|_ database
|  |_ db.txt
|  |_ make_db.py
|
|_ accessory
|  |_ util.py
|
|_ explore_one_way
|  |_ script1.py
|
|_ explore_a_second_way
   |_ script2.py

How do I access, say, util.py from script1.py? Is there another way than adding to sys.path or is that the most pythonic?

Update: This is relatively painless. I added __init__.py to the accessory directory and can then do:

import sys
sys.path.insert(0, '..')
from proj import util

or

from proj.util import some_symbol

Thanks to all.

MertG · Accepted Answer · 2020-05-04 20:57:09Z

2

Firstly, you should create empty __init__.py file each folder. Then add the top of your script1.py file as below.

import sys 
sys.path.insert(0, ".")

from accessory import util.py

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answered May 4, 2020 at 20:57

MertG

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1 Comment

telliott99 Over a year ago

I think you want ".."

Frederik Bode · Accepted Answer · 2020-05-04 20:59:35Z

1

You can:

add sys.path ((-) not very pythonic vs (+) easy)
use soft links ((-) sometimes gives issues with docker vs (+) you can link to directories). Soft links are a files that are like copies of other files, but not real copies (like a shallow copy). There's always only one copy of the file ever.
use hard links ((-) need to link every file, no directories vs (+) no docker issues). Hard links are actual copies that sync their clones if you change either one of them.

I recommend soft links if you don't like __init__.py and sys.path!

answered May 4, 2020 at 20:59

Frederik Bode

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1 Comment

telliott99 Over a year ago

I was afraid of that.

Subir Verma · Accepted Answer · 2020-05-04 21:10:04Z

0

from accessory import util

answered May 4, 2020 at 21:10

Subir Verma

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2 Comments

telliott99 Over a year ago

This raises ImportError.

Subir Verma Over a year ago

Not sure if you are maintaining the same directory structure. But try from .accessory import util

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