Format a pattern string to display in desired format in Python

Question

I do have a date and time format printed in '2020-05-06T15:16:24+05:30' which I would like to display in python in the format of YYYY-MMM-DD HH:MM:SS. Any pointers would be highly appreciated.

Does this answer your question? Parse date string and change format — mkrieger1
– mkrieger1, Commented May 6, 2020 at 9:58

AKX · Accepted Answer · 2020-05-06 10:00:16Z

1

You have an ISO8601 datetime; yse the datetime module to parse a datetime object out of it, then format as required.

Note the timezone information is "hidden" in your desired formatting, but exists in that tzinfo property.

>>> s = '2020-05-06T15:16:24+05:30'
>>> import datetime
>>> t = datetime.datetime.fromisoformat(s)
datetime.datetime(2020, 5, 6, 15, 16, 24, tzinfo=datetime.timezone(datetime.timedelta(seconds=19800)))
>>> t.strftime("%Y-%m-%d %H:%M:%S")
'2020-05-06 15:16:24'
>>>

answered May 6, 2020 at 10:00

AKX

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2 Comments

mss tdy Over a year ago

I do get this error Traceback (most recent call last): File "<pyshell#3>", line 1, in <module> t = datetime.datetime.fromisoformat(s) AttributeError: type object 'datetime.datetime' has no attribute 'fromisoformat'

AKX Over a year ago

fromisoformat was added in Python 3.7. If you have an older Python, you'll need the iso8601 module's parse_date function: pypi.org/project/iso8601

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