I have this dictionary_pair and a list_value. I want to be able to use lambda, filter to get a list as [1,2]. I have tried the code below but getting a list as ['ab'].
dictionary_pair = {'ab': [1, 2], 'cd': [3, 1]}
list_value = ['ab', 'yz']
try:
result = list(filter(lambda x: dictionary_pair[x], list_value))
except KeyError:
pass
This is just to show you how to use lambda, map, filter. However a simple list-comprehension is preferred in this case
list(filter(None, map(lambda x:dictionary_pair.get(x, None) ,list_value)))
#[[1, 2]]
I'm assuming you want something like this:
result = [v for k, v in dictionary_pair.items() if k in list_value]
No need to use a lambda, a simple list comprehension works here.
