I have a list as follows :
[{"1": {"movie": "0.53"}}, {"2": {"movie": "5.2"}}, {"3": {"movie": "3.2"}}]
And I know how to do t = sorted(new_list, key=lambda i: float(i['1']['movie']), reverse=True)
but I am unsure on how can i also have the 1 ,2 , 3 as iteration ^
What you could do is convert the inner dictionaries to a list from dict.values(), select the first value, then access the "movie" key. Then pass this as a float to the key function of sorted:
l = [{"1": {"movie": "0.53"}}, {"2": {"movie": "5.2"}}, {"3": {"movie": "3.2"}}]
result = sorted(l, key=lambda x: float(list(x.values())[0]["movie"]))
print(result)
Another option is to convert your list of dicts to a list of lists, sort the result from the resulting list dict.items(), then convert the result back to a list of dicts:
l = [{"1": {"movie": "0.53"}}, {"2": {"movie": "5.2"}}, {"3": {"movie": "3.2"}}]
result = [
dict(l)
for l in sorted((list(d.items()) for d in l), key=lambda x: float(x[0][1]["movie"]))
]
print(result)
Which can also just use a basic dict.update approach to convert the list of dicts to a nested dict before sorting:
l = [{"1": {"movie": "0.53"}}, {"2": {"movie": "5.2"}}, {"3": {"movie": "3.2"}}]
dicts = {}
for d in l:
dicts.update(d)
# {'1': {'movie': '0.53'}, '2': {'movie': '5.2'}, '3': {'movie': '3.2'}}
result = [{k: v} for k, v in sorted(dicts.items(), key=lambda x: float(x[1]["movie"]))]
print(result)
Or if we want to do it in one line, we can make use of collections.ChainMap:
from collections import ChainMap
l = [{"1": {"movie": "0.53"}}, {"2": {"movie": "5.2"}}, {"3": {"movie": "3.2"}}]
result = [
{k: v} for k, v in sorted(ChainMap(*l).items(), key=lambda x: float(x[1]["movie"]))
]
print(result)
Output:
[{'1': {'movie': '0.53'}}, {'3': {'movie': '3.2'}}, {'2': {'movie': '5.2'}}]
Btw the list that you have posted is incorrect in syntax, assuming it to be list of dictionaries. You can sort it like following:
new_list = [
{"1":{"movie": "0.53"}},
{"2":{"movie": "5.2"}},
{"3":{"movie": "3.2"}}
]
t = sorted(new_list, key=lambda x: float(list(x.items())[0][1]['movie']))
Output:
[{'1': {'movie': '0.53'}}, {'3': {'movie': '3.2'}}, {'2': {'movie': '5.2'}}]
keyof each dict?ints?[{"1": {"movie": "0.53"}}, {"2": {"movie": "5.2"}}, {"3": {"movie": "3.2"}}]