How to use regexp on file, line by line, in Python

The following expression returns a list; every entry of that list contains all matches of your regexp in the respective line.

>>> import re
>>> [re.findall(r'f\(\s*([^,]+)\s*,\s*([^,]+)\s*\)',line) 
            for line in open('file.txt')]

You can try something like this :

import re
regex = re.compile("f\(\s*([^,]+)\s*,\s*([^,]+)\s*\)")
with open("my_file.txt") as f:
    for line in f:
        result = regex.search(line)

import re
with open('file.txt') as f:
    for line in f:
        match = re.search('f\(\s*([^,]+)\s*,\s*([^,]+)\s*\)', line)

Note that Python automatically compiles and caches the regex, so a separate compile step is not required in this case.

Another way to do

import re
[line for line in open('file.txt') if re.match(r'f\(\s*([^,]+)\s*,\s*([^,]+)\s*\)',line)]

use import re, then re.compile() with your pattern as an argument, and use the resulting object's match attribute on each line. something like this..

import re 
pat = re.compile(r'f\(\s*([^,]+)\s*,\s*([^,]+)\s*\)')
for line in file:
  # use pat.match, pat.search .. etc

for line in file:
   line = re
           .match("f\(\s*([^,]+)\s*,\s*([^,]+)\s*\)",line)
           .group(0)

I have used this aproach:

import re
#Define the search term:
pattern = r"f\(\s*([^,]+)\s*,\s*([^,]+)\s*\)" #pattern must be enclosed in quotes

#Create an empty list:
data = []

#then

for line in open(r'file.txt'):
    if line.strip():  #<-- To make sure the whole file is read
        word = re.findall(pattFinder1, line)
        data.append(str(word))