var string = '12345';
I want to replace 2 and 4 with 0, so I tried:
var output = string.replaceAll('2, 4', '0') // doesn't work
I am not sure if I need to use RegExp for this small stuff? Is there any other way to solve this?
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2 Answers
You can achieve this with RegExp:
final output = string.replaceAll(RegExp(r"[24]"),'0');
[24] matches any character that is either 2 or 4.
4 Comments
iDecode
What if I want to use string interpolation in it, how will that work? For instance: I want to replace a variable
RegExp(r"[$variable 4]", '0')iDecode
I am unaccepting this answer because I am not able to use string interpolation part in it.
Eiko
This can easily be fixed, just use
RegExp("[${variable}4]", '0'). I mean the r is just denoting a raw string here. You are quite new to this site, so maybe check the rules here. Changing the question is highly discouraged, as this makes the answers and efforts potentially useless or inappropriate. Better to ask a new question.iDecode
You're right, I shouldn't have upvoted and accepted your answer in the first place, I was very kind to you but thanks for teaching me a lesson :)
This works
void main() {
var string = '12345';
string = string.replaceAll('2', "0");
string = string.replaceAll('4', "0");
print(string);
}
1 Comment
iDecode
Thanks but this isn't what I am looking for, I could also have done it 2 times.