Must be simple but cant find my answer.
How to test whether one of the values in the array is contained in the string?
Output should be true or false.
$array = Array(
0 => 'word1',
1 => 'word2',
2 => 'New York'
3 => 'New car'
);
$string = "Its a sunny day in New York";
Trying to clarify. In this case array[3] should not be a match. Only array[2] should be.
The functional replacement for your in_array would be:
array_filter(
array_map("strpos", array_fill(0, count($words), $string), $words),
"is_int")
Update:
A word boundary independent solution would be to add spaces around the input string and the search words:
$str = ' ' . $str . ' ';
function quote($a) {
return ' ' . preg_quote($a, '/') . ' ';
}
$word_pattern = '/' . implode('|', array_map('quote', $array)) . '/';
if(preg_match($word_pattern, $str) > 0) {
}
or by looping over the terms:
foreach($array as $term) {
if (strpos($str, ' '. $term . ' ') !== false) {
// word contained
}
}
Both can be put in a function to simplify the use, e.g.
function contains($needle, $haystack) {
$haystack = ' ' . $haystack . ' ';
foreach($needle as $term) {
if(strpos($haystack, ' ' . $term . ' ') !== false) {
return true;
}
}
return false;
}
Have a look at a DEMO
Old answer:
You could use regular expressions:
function quote($a) {
return preg_quote($a, '/');
}
$word_pattern = implode('|', array_map('quote', $array));
if(preg_match('/\b' . $word_pattern . '\b/', $str) > 0) {
}
The important part are the boundary characters \b here. You will only get a match if the value you search for is a (sequence of) word(s) in the string.
A brute force method would be:
$words = implode('|', $array);
if (preg_match("/($words)/", $string, $matches)) {
echo "found $matches[1]";
}
preg_quote.$array = Array(
0 => 'word1',
1 => 'word2',
2 => 'word3'
);
$string = "there a good word3 here";
foreach($array as $word)
{
if(strstr($string, $word))
echo "<b>$word</b> has been detected in <b>$string</b>";
}
You can se the in_array function for that: http://php.net/manual/en/function.in-array.php
if (in_array($value, $array))
{
echo $value . ' is in the array!';
}
The code I've got work only works for an exact match (and is the wrong way) so output here would be false but I need a true... Sorry$array = Array(
0 => 'word1',
1 => 'word3',
2 => 'word3 basic',
3 => 'good'
);
$string = "there a good word3 basic here";
//Convert the String to an array
$stringArray = explode(' ',$string);
//Loop the string
foreach($stringArray as $matchedWords) {
if(in_array($matchedWords, $array )) {
echo $matchedWords.'<br/>';
}
}
Something like this?
$array = Array(
0 => 'word1',
1 => 'word2',
2 => 'word3'
);
$string = "there a good word3 here";
function findInArray($string, $array) {
for ($x=0; $x < count($array); $x++) {
if (preg_match('/\b' . $array[$x] . '\b/', $string)) { // The \b in the pattern indicates a word boundary, so only the distinct
return true;
}
}
return false;
}
if (findInArray($string, $array)) {
// do stuff
}
