Im trying to add each values of score to the dict names i,e score[0] to names[0] and so on...
names=[{'id': 1, 'name': 'laptop'}, {'id': 2, 'name': 'box'}, {'id': 3, 'name': 'printer'}]
score = [0.9894376397132874, 0.819094657897949, 0.78116521835327]
Output should be like this
names=[{'id': 1, 'name': 'laptop','score':0.98}, {'id': 2, 'name': 'box','score':0.81}, {'id': 3, 'name': 'printer','score':0.78}]
How to achieve this? thanks in advance
I'd do it with a comprehension like this:
>>> [{**d, 'score':s} for d, s in zip(names, score)]
[{'id': 1, 'name': 'laptop', 'score': 0.9894376397132874}, {'id': 2, 'name': 'box', 'score': 0.819094657897949}, {'id': 3, 'name': 'printer', 'score': 0.78116521835327}]
d is a dict from the list of dicts names.Without list comprehension.
for i, name in enumerate(names):
name['score'] = score[i]
print(names)
This is an easy-to-understand solution. From your example, I understand you don't want to round up the numbers but still want to cut them.
import math
def truncate(f, n):
return math.floor(f * 10 ** n) / 10 ** n
names=[{'id': 1, 'name': 'laptop'}, {'id': 2, 'name': 'box'}, {'id': 3, 'name': 'printer'}]
score = [0.9894376397132874, 0.819094657897949, 0.78116521835327]
n = len(score)
for i in range(n):
names[i]["score"] = truncate(score[i], 2)
print(names)
If you do want to round up the numbers:
names=[{'id': 1, 'name': 'laptop'}, {'id': 2, 'name': 'box'}, {'id': 3, 'name': 'printer'}]
score = [0.9894376397132874, 0.819094657897949, 0.78116521835327]
n = len(score)
for i in range(n):
names[i]["score"] = round(score[i], 2)
print(names)