This code:
cout<< to_string(x) + "m ----> " + to_string(x *0.001)+ "km"<<endl;
with this outputting:
0.002000
However, I want to remove the trailing extra zeros, but it should be in a line of code as i have many lines like the above one.
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Any helpful comments ~ Much appreciated !3.00AMCoder– 3.00AMCoder2020-05-25 05:05:53 +00:00Commented May 25, 2020 at 5:05
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2 Answers
try this snipet:
cout << "test zeros" << endl;
double x = 200;
cout << "before" << endl;
cout<< std::to_string(x) + "m ----> " + std::to_string(x *0.001)+ "km"<<endl;
std::string str = std::to_string(x * 0.001);
str.erase ( str.find_last_not_of('0') + 1, std::string::npos );
cout << "after" << endl;
cout<< std::to_string(x) + "m ----> " + str + "km"<<endl;
with output:
test zeros
before
200.000000m ----> 0.200000km
after
200.000000m ----> 0.2km
it is better then std::setprecision cause you don't need to decide how many num after period you want to keep, but let the implementation find it for you.
Here the documentation for some extra information.
Comments
Try using std::setprecsion()
Set decimal precision
Sets the decimal precision to be used to format floating-point values on output operations.
So in your case, you can use :
std::cout << std::setprecision(3)
This will remove the trailing zeroes from 0.0020000 to 0.002
Edit
The below code works when you want to use to_string in your code :
#include <iostream>
using namespace std;
int main(){
int x=1;
string str2 = to_string(x *0.001);
str2.erase ( str2.find_last_not_of('0') + 1, std::string::npos );;
std::cout<<to_string(x)+ "m ----> " + str2+ "km";
}
6 Comments
3.00AMCoder
cout<<to_string(x) + "m ----> " + to_string(x *0.001)+ "km"<<endl; How to implement that in this code? i tried 2 ways, didnt worked.
@3.00AMCoder It seems like you don't need to use
to_string at all in your code. As explained in the duplicate question, you can't prevent to_string from adding trailing zeros. If you do cout << x << "m ----> " << x * 0.001 << "km" << endl though you can control the formatting with things like setprecision.3.00AMCoder
@BessieTheCow yepppp thank you, works prefectly!
Abhishek Bhagate
Well, to edit my answer, they below code works : #include <iostream> using namespace std; int main(){ int x=1; std::string str1 = std::to_string (x); string str2 = to_string(x *0.001); str1.erase ( str1.find_last_not_of('0') + 1, std::string::npos ); str2.erase ( str2.find_last_not_of('0') + 1, std::string::npos ); std::cout<<str1 + "m ----> " + str2+ "km"; }
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