I have a code below
#include <iostream>
void print(int n){
if(n == 0) {return;}
for(int i=0; i<n; i++)
cout<<"Hello world"<<endl;
}
int main(){
print(n);
}
What it does is it prints "Hello world" using for loop n times. My question is would it be possible to print it using recursion instead of using for loop?
You can adapt your code like this. The print function will be called recursively n times, then return since in the last call n will be equal to 0 and because of the first condition it will stop the recursion.
#include <iostream>
void print(int n) {
if(n == 0) { return; }
std::cout << "Hello world" << std::endl;
print(n-1);
}
int main(){
print(n);
}
Recursion is simply a function that calls itself. There's a pretty good tutorial HERE.
Basically, you would create a counter, and add to that counter every time the function is called, and don't call it from inside itself if the counter is higher than a certain value.
I would simply do something like this:
#include <iostream>
void print(int n){
if(n!=0){
std::cout<<"Hello world"<<std::endl;
return print(n-1);
}
}
int main(){
print(n);
return 0;
}
forpart, and after thecoutaddprint(n-1);.if(n == 0) {return;}is unneeded.