Python: How to check if element of string is in a string and print the not included string elements?

Question

I want to check each list element of c in alphabet and print the letters of the alphabet, which are not in a list element of c.

For example, shall the first list element of c "aa" print all letters of alphabet in a string excluding the letter a.

alphabet = "abcdefghijklmnopqrstuvwxyz"   
c = ['aa', 'bb', 'zz']

for x in c:
  if x in alphabet:
    print(alphabet)
  else:
    print('not an element of alphabet')

Do you mean for for aa it should print bcdefghijklmnopqrstuvwxyz and for bb the string acdefghijklmnopqrstuvwxyz? — Code Pope
– Code Pope, Commented May 27, 2020 at 15:14

piertoni · Accepted Answer · 2020-05-27 15:24:37Z

2

Something like that:

alphabet = "abcdefghijklmnopqrstuvwxyz"   
cases = ['aa', 'bb', 'zz']

for case in cases:
    missing_letters = []
    for letter in alphabet:
        if letter not in case:
            missing_letters.append(letter)
    print(f"Case {case} misses following alphabeth letters {missing_letters}")

Output:

Case aa misses following alphabeth letters ['b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

answered May 27, 2020 at 15:24

piertoni

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Comments

Code Pope · Accepted Answer · 2020-05-27 15:41:02Z

2

If you are sure that the elements in c are all in the format of 'xx' like in your sample, then the following is a solution:

alphabet = "abcdefghijklmnopqrstuvwxyz"   
c = ['ad', 'bb', 'zz','ad', 'bt', 'uz']

for x in c:
  new_alph = alphabet
  for char in x:
    new_alph = new_alph.replace(char,'')
  if new_alph == alphabet:
    print('not an element of alphabet')
  else:
    print(new_alph)

Output:

bcefghijklmnopqrstuvwxyz
acdefghijklmnopqrstuvwxyz
abcdefghijklmnopqrstuvwxy
bcefghijklmnopqrstuvwxyz
acdefghijklmnopqrsuvwxyz
abcdefghijklmnopqrstvwxy

Another way is to use translate to make the code more compact:

alphabet = "abcdefghijklmnopqrstuvwxyz"   
c = ['ad', 'bb', 'zz','ad', 'bt', 'uz']

for x in c:
  new_alph = alphabet.translate({ord(char): '' for char in x})
  if new_alph == alphabet:
    print('not an element of alphabet')
  else:
    print(new_alph)

Output:

bcefghijklmnopqrstuvwxyz
acdefghijklmnopqrstuvwxyz
abcdefghijklmnopqrstuvwxy
bcefghijklmnopqrstuvwxyz
acdefghijklmnopqrsuvwxyz
abcdefghijklmnopqrstvwxy

edited May 27, 2020 at 15:41

answered May 27, 2020 at 15:20

Code Pope

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3 Comments

Leini Over a year ago

Looks great! Thanks! and if I have two different letters in one list element: c = ['ad', 'bt', 'uz']

Code Pope Over a year ago

@StephanLeinert Ok, now I understand your goal. I have updated the code. You will get the desired result. The solution will work for any length the elements in c have.

Code Pope Over a year ago

@StephanLeinert I have also added another more compact way to do the job. See the edited version.

HackLab · Accepted Answer · 2020-05-27 15:23:19Z

0

As long as the strings in c are only 2 chars this will work

alphabet = "abcdefghijklmnopqrstuvwxyz"   
c = ['aa', 'bb', 'zz']

for x in c:
  if x[0] in alphabet or x[1] in alphabet:
    alphabet.replace(x[0], '').replace(x[1], '')
  else:
    print('not an element of alphabet')

answered May 27, 2020 at 15:23

HackLab

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