Remove an ID if a input value is = some defined code

Question

I want to remove an input id when another input id having value in defined values

my codes

setInterval(function() {
  var MaterialGod = [
    "FPPUTHP1100000",
    "FPPUTHP1100000",
    "FPPUTHP1110000",
    "FPPUTHP1500000",
    "FPPUTHP1680000",
    "FPPUTHP1690000",
    "FPPUTHP1590000"
  ];

  $.each(MaterialGod, function(index) {
    if ($("label:contains('Meterial Code')").parent().next().find('input').val() == index) {
      $('#__item5-__box2-0').remove();
    }
  })
}, 100);

Pls give your advise what i m doing wrong

index is the array index, not the value of the array element. — Barmar
– Barmar, Commented May 28, 2020 at 18:51
The second argument to the callback function is the element. — Barmar
– Barmar, Commented May 28, 2020 at 18:51

Martijn Pieters · Accepted Answer · 2021-05-07 00:52:44Z

2

If am not wrong you are comparing with index instead of value. Try comparing with value as shown in below code.

  setInterval(function() {
      var MaterialGod = [
        "FPPUTHP1100000",
        "FPPUTHP1100000",
        "FPPUTHP1110000",
        "FPPUTHP1500000",
        "FPPUTHP1680000",
        "FPPUTHP1690000",
        "FPPUTHP1590000"
      ];
    
      $.each(MaterialGod, function(index,iVal) {
        if ($("label:contains('Meterial Code')").parent().next().find('input').val() == iVal) {
          $('#__item5-__box2-0').remove();
        }
      })
    }, 100);

edited May 7, 2021 at 0:52

Martijn Pieters

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answered May 28, 2020 at 19:12

Satinder singh

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Comments

Barmar · Accepted Answer · 2020-05-28 18:54:36Z

1

You're comparing the array index, not the array element, with the value.

There's also no reason to put the selector in the loop, since you're selecting the same input every time.

Just get the input value, and use .includes() to see if it's in the array.

setInterval(function() {
  var MaterialGod = [
    "FPPUTHP1100000",
    "FPPUTHP1100000",
    "FPPUTHP1110000",
    "FPPUTHP1500000",
    "FPPUTHP1680000",
    "FPPUTHP1690000",
    "FPPUTHP1590000"
  ];
  if MaterialGod.includes($("label:contains('Meterial Code')").parent().next().find('input').val()) {
    $('#__item5-__box2-0').remove();
  }
}, 100);

answered May 28, 2020 at 18:54

Barmar

789k57 gold badges555 silver badges669 bronze badges

10 Comments

Sachin Agarwal Over a year ago

Its Worked Fine... Thanks :) I am a new user so cant vote UP

Barmar Over a year ago

@SachinAgarwal You've changed the question completely. If you have a different problem, post a new question.

Sachin Agarwal Over a year ago

@Barmar I m a new user stackoverflow banned me for asking new question....it was very urgent

Barmar Over a year ago

$(this).find("option:selected").text() contains the text of the selected option. You can show that in the other place.

Sachin Agarwal Over a year ago

@Barmar its not working.. may be i am doing something wrong.. can you post the whole code here?

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