Printing out values of different rows and column in 2d array using for loops

Question

I have this 2d array of the first row being first names and the second being last names.

String[][] ladrones2 = {
        {"Phil", "Kim", "Phil", "Perry"},
        {"Garcia", "Gimena", "Basinger", "Ornitorrinco"}};

the prefered out come of this would be to have them printend out like e.g

Phill Garcia
Kim Gimena
etc...

Now I was able to do this by catching the ArrayIndexOutOfBoundsException exception and it works and the output is:

name Phil Garcia
name Kim Gimena
name Phil Basinger
name Perry Ornitorrinco

Which is great but I wondered if there was a way to do this without having to catch the exception? I've been searching to make this cleaner but wasn't able to do so.

Code at the moment:

public static void robo2() {
    String[][] ladrones2 = {
            {"Phil", "Kim", "Phil", "Perry"},
            {"Garcia", "Gimena", "Basinger", "Ornitorrinco"}};

    try {
        for (int i = 0; i < ladrones2.length; i++) {
            for (int j = 0; j < ladrones2[i].length; j++) {
                System.out.println("name: " + ladrones2[i][j] + " " + ladrones2[i + 1][j]);
            }
        }
    } catch (ArrayIndexOutOfBoundsException e) {
        System.out.println("");
    }
}

as you can see I used in the inner for loop a +1 on the i variable which in turn throws the exception.

Any ideas? I would like just to keep this way of working at the moment with 2 forloops due to being new to Java.

Community · Accepted Answer · 2021-06-11 14:58:29Z

1

If you are sure that ladrones2 array always has 2 rows, then below code would be simpler:

public static void main(String[] args) {
    String[][] ladrones2 = {
            {"Phil", "Kim", "Phil", "Perry"},
            {"Garcia", "Gimena", "Basinger", "Ornitorrinco"}};

    for (int i = 0; i < ladrones2[0].length; i++) {
        System.out.println("name: " + ladrones2[0][i] + " " + ladrones2[1][i]);
    }
}

edited Jun 11, 2021 at 14:58

CommunityBot

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answered May 30, 2020 at 15:39

Sudhir

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4 Comments

Samuel Van Bladel Over a year ago

Hi Sundhir , nice I got the same output thanks for the advice. I just have one more question I don't seem to understand here. Why are we still putting [0] after ladrones2 in the for loop? Wouldn't that not be used only on the inner for loop if you would use one ? Thanks for the help already.

Sudhir Over a year ago

@SamuelVanBladel [0] gives name count in each row. This is required to stop the loop once all names are printed. Hope this helps.

Samuel Van Bladel Over a year ago

Hi Sudhir, thanks for the quick reply but what do you mean with "name count" ?

Sudhir Over a year ago

@SamuelVanBladel "name count" - number of elements (names) in each row of the 2d array

Simon Gaufreteau · Accepted Answer · 2020-05-30 15:43:31Z

1

On this line :

System.out.println("name: " + ladrones2[i][j] + " " + ladrones2[i + 1][j]);

You are taking an element from the first and second array at the same time but you are looping over all the elements in the sequence on this line :

for (int i = 0; i < ladrones2.length; i++)

To correct this problem, you simply have to reduce the range of i to ladrones.length-1, otherwise you will reach the end of the array and try to access the next element which doesn't exist here.

You'll end up with this line instead :

for (int i = 0; i < ladrones2.length-1; i++) {

answered May 30, 2020 at 15:43

Simon Gaufreteau

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2 Comments

Samuel Van Bladel Over a year ago

Hi Simon, I've added the -1 to my outer for loop but now I get the following output. name: Phil Garcia name: Kim Garcia name: Phil Garcia name: Perry Garcia As yiu can see the second row gets stuck on 1 - 0

Simon Gaufreteau Over a year ago

You probably did something wrong here. If you followed my advices, you should have written the following code :

Java for (int i = 0; i < ladrones2.length-1; i++) {     for (int j = 0; j < ladrones2[i].length; j++) {System.out.println("name: " + ladrones2[i][j] + " " + ladrones2[i + 1][j]); 			} 		}

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