How can I do a regex pattern for Hibernate validation?

Question

I want to use a regex @Pattern with Hibernate validation. How can I do this regex expression?

[a][b][c][d][e] is a number with 13 digits like this: 1831222132132

a - one digit, 1 or 2, nothing else;
b - from 01 to 99, it is the last 2 digits from the year, for ex 1983 => b = 83;
c - from 01 to 12;
d - from 01 to 31;
e - 6 digits;

Any help will be appreciated. Thank you!

AYRM1112013 · Accepted Answer · 2020-06-01 15:44:11Z

3

To validate that in Hibernate you can use @Pattern annotation like this

@Column(name = "myInpt")
@Pattern(regexp = "^[12](0[1-9]|[1-9][0-9])(0[1-9]|1[012])(0[1-9]|[12][0-9]|3[01])([0-9]{6})$", message = "Incorrect format")
private String myInput;

answered Jun 1, 2020 at 15:44

AYRM1112013

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3 Comments

elvis Over a year ago

Thank you! Can you tell me how can I do to show the error message in the response body? Now the message is empty { "timestamp": "2020-06-03T17:20:20.721+00:00", "status": 400, "error": "Bad Request", "message": "", "path": "/ibantoiban" }

AYRM1112013 Over a year ago

In your controller, you should use @valid annotation. Also, you make sure you do not overwrite the default behavior of exception handling in your code. code example:

AYRM1112013 Over a year ago

@PostMapping("/zzz") public ResponseEntity<ZZZ> addzzz(@Valid @RequestBody ZZZ zzz)

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