Get which file doesn't exist with file_exists but using an array

Question

Well,

I have a script, that checks if one of the files in the array exists or not.

But now I don't know how to get the file, from the array that doesn't exist. Here's an example:

<?php
$files = [
   "user/important.ini",
   "user/really_needed.php"
];

if(file_exists($files) == false) {
   $data = "1";
   $meta = array(
       "file" => ????,
       "error" => "Missing file"
    );

?>

So I'd like to "replace" the "????" with the file that doesn't exists, since I don't know how to get this file, it's those question marks.

Is there possible code I could use, to get the file that doesn't exist?

file_exists takes a string (filename) not an array. You will have to loop over your filenames in $files. In case the check fails for a certain file, you will have its name right there in the loop. — RST
– RST, Commented Jun 3, 2020 at 12:04

Nigel Ren · Accepted Answer · 2020-06-03 12:05:13Z

2

file_exists() expects a file name and if you use an array (as you currently do) you should get a warning...

Warning: file_exists() expects parameter 1 to be a valid path, array given

This assumes that you want all of the files that don't exist and keeps a list of the failures. It uses foreach() over the array and tests each item, adding it to the list if it doesn't exist using $meta[] (don't forget to initialise this array before the loop) ...

$files = [
        "user/important.ini",
        "user/really_needed.php"
];
$meta = [];
foreach ( $files as $file ) {
    if(file_exists($file) == false) {
        $data = "1";
        $meta[] = array(
                "file" => $file,
                "error" => "Missing file"
        );
    }
}

print_r($meta);

answered Jun 3, 2020 at 12:05

Nigel Ren

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Comments

Franix · Accepted Answer · 2020-06-03 12:15:29Z

1

Looping over the files to check if they exist is one way this could be done. I suggest using a foreach loop here.

<?php
$files = [
   "user/important.ini",
   "user/really_needed.php"
];

$meta = [];
foreach ($files as $file) {
   if(!file_exists($file) {
      $data = "1";
      $meta[] = array(
         "file" => $file,
         "error" => "Missing file"
      );
?>

edited Jun 3, 2020 at 12:15

answered Jun 3, 2020 at 12:05

Franix

1038 bronze badges

2 Comments

RST Over a year ago

There is an error in your code. $meta will only hold the last missing file. Add [] to the variable name.

Franix Over a year ago

Right, forgot he was checking multiple files. Thanks for the heads up <3

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