Dynamically print spaces/tabs in python

Question

have a scenario

df has 5 rows

for i in range(len(df)):
    print ("\t", i, "Time")

need the output to look like

 0 Time
      1 Time
           2 Time
                3 Time
                     4 Time

How do we make python add the tabs depending on the counter value? Is there a way to do this?

You can multiply the tab by i like so: print ("\t" * i, i, "Time") — Loocid
– Loocid, Commented Jun 4, 2020 at 5:28

Coder1238 · Accepted Answer · 2020-06-04 05:32:21Z

1

You could try multiplying of string which would give i no of tabs:

for i in range(len(df)):
    print ("\t"*i, i, "Time")

answered Jun 4, 2020 at 5:32

Coder1238

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Comments

tersrth · Accepted Answer · 2020-06-04 05:32:50Z

1

Simple change:

for i in range(len(df)):
    print ("\t"*i, i, "Time")

answered Jun 4, 2020 at 5:32

tersrth

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