How to calculate how many items in a foreach?
I want to count total rows.
foreach ($Contents as $item) {
$item[number];// if there are 15 $item[number] in this foreach, I want get the value : 15
}
-
Does every item has a number?Gumbo– Gumbo2011-06-02 21:24:04 +00:00Commented Jun 2, 2011 at 21:24
-
foreach is a php construct, and doesn't have any items - arrays do. using count($array) returns the number of elements in it.J.C. Inacio– J.C. Inacio2011-06-02 21:31:19 +00:00Commented Jun 2, 2011 at 21:31
Add a comment
|
11 Answers
If you just want to find out the number of elements in an array, use count. Now, to answer your question...
How to calculate how many items in a foreach?
$i = 0;
foreach ($Contents as $item) {
$item[number];// if there are 15 $item[number] in this foreach, I want get the value : 15
$i++;
}
If you only need the index inside the loop, you could use
foreach($Contents as $index=>$item) {
// $index goes from 0 up to count($Contents) - 1
// $item iterates over the elements
}
1 Comment
kapitan
i just did
$index+1 for the row number, exactly what i need, thanks!You don't need to do it in the foreach.
Just use count($Contents).
count($Contents);
or
sizeof($Contents);
1 Comment
Richard
Don't use
sizeof, it's just an alias to the real thing and can cause confusion: php.net/manual/en/function.sizeof.phpforeach ($Contents as $index=>$item) {
$item[$index];// if there are 15 $item[number] in this foreach, I want get the value : 15
}
Comments
There's a few different ways you can tackle this one.
You can set a counter before the foreach() and then just iterate through which is the easiest approach.
$counter = 0;
foreach ($Contents as $item) {
$counter++;
$item[number];// if there are 15 $item[number] in this foreach, I want get the value : 15
}
1 Comment
Jeffrey Kastner
var in PHP is wrong. (this isn't a JavaScript question)
Try:
$counter = 0;
foreach ($Contents as $item) {
something
your code ...
$counter++;
}
$total_count=$counter-1;
Comments
You can do sizeof($Contents) or count($Contents)
also this
$count = 0;
foreach($Contents as $items) {
$count++;
$items[number];
}
Comments
$Contents = array(
array('number'=>1),
array('number'=>2),
array('number'=>4),
array('number'=>4),
array('number'=>4),
array('number'=>5)
);
$counts = array();
foreach ($Contents as $item) {
if (!isset($counts[$item['number']])) {
$counts[$item['number']] = 0;
}
$counts[$item['number']]++;
}
echo $counts[4]; // output 3
Comments
foreach ($array as $value)
{
if(!isset($counter))
{
$counter = 0;
}
$counter++;
}
//Sorry if the code isn't shown correctly. :P
//I like this version more, because the counter variable is IN the foreach, and not above.
Comments
Imagine a counter with an initial value of 0.
For every loop, increment the counter value by 1 using $counter = 0;
The final counter value returned by the loop will be the number of iterations of your for loop. Find the code below:
$counter = 0;
foreach ($Contents as $item) {
$counter++;
$item[number];// if there are 15 $item[number] in this foreach, I want get the value `: 15`
}
Try that.
1 Comment
B--rian
Welcome to SO! Please edit your question and explain a bit why it solves the issue and how. For more guidance, see stackoverflow.com/help/how-to-ask
$index = 0;
foreach( $array ?? [] as $index=> $item ) {
$index++;
$data[] = array(
'id' =>$index
);
}