gprc client async response NodeJS

Question

I'm trying to call a simple grpc request in a function but I don't know how to wait for the response and pass it outside the grpc call.

It should be something like that:

Client: (parent, args, context, info) =>{
      client.Get({thing, objects, properties}, function(err, response) {
            //how to return the response outside?
          });
      //await for the response function.
};

Is it possible to return the response in some way outside the client.Get function? Does someone have some suggestions? Thank you in advice!

Lin Du · Accepted Answer · 2020-08-28 10:57:38Z

10

You have two ways:

Wrap the methods of gRPC from error first callback to promise by yourself.

new Promise((resolve, reject) => client.Get({thing, objects, properties}, function(err, response) {
  if(err) {
    return reject(err)
  }
  resolve(response)        
}))

Use grpc-promise to promisify the methods of gRPC client.

const grpc_promise = require('grpc-promise');;
grpc_promise.promisifyAll(client);

Then, you can pass this promisified gRPC client to GraphQL context. (Guess you are using GraphQL based on the function signature).

Then you can return a promise in a GraphQL resolver.

Client: (parent, args, context, info) =>{
  return context.client.Get({thing, objects, properties})
};

edited Aug 28, 2020 at 10:57

answered Aug 28, 2020 at 10:51

Lin Du

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