I put some classes(wow) in list a.
And I want to print the variable num of all elements of a without using for statement.
What should I do?
I want to(example):
[1,5,3,4,0] # Expected output
What I have tried:
import random as r
class wow():
def __init__(self):
self.num=r.randint(0,10)
a=[]
for x in range(5):
a.append(wow())
print((lambda x: x)(a).num)
You can add __str__() method to your class:
class wow():
def __init__(self):
self.num=r.randint(0,10)
def __str__(self):
return str(self.num)
then by just printing:
print(*a)
you will get:
3 9 4 9 3
in addition, reading this Link might be good for better clue:
print(list(map(lambda x: x.num, a)))
I don't recommend this, but you can use map with a lambda function.
import random as r
class wow():
def __init__(self):
self.num=r.randint(0,10)
a=[]
for x in range(5):
a.append(wow())
_ = list(map(lambda x: print(x.num, end=' '), a))
# prints:
2 8 0 6 5
You can also use a while loop and catch the StopIteration.
g = iter(a)
while True:
try:
print(next(g).num, end=' ')
except StopIteration:
break
You might harness operator.attribgetter for that task following way:
import operator
import random
class wow:
def __init__(self):
self.num=random.randint(0,10)
a=[]
for x in range(5):
a.append(wow())
print(*map(operator.attrgetter('num'),a))
Output:
4 3 9 8 8
for?