I need to create a point graph using the "ggplot" library based on a binary column of a dataframe.
df <- c(1,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,0,1)
I need a point to be created every time the value "1" appears in the column, and all points are on the same graph. Thanks.
If the binary column you talk about is associated to some other variables, then I think this might work:
(I've just created some random x and y which are the same length as the binary 0, 1s you provided)
x <- rnorm(22)
y <- x^2 + rnorm(22, sd = 0.3)
df <- data.frame("x" = x, "y" = y,
"binary" = c(1,0,1,0,0,0,0,0,0,0,1,0,0,0,0,0,1,0,0,0,0,1))
library(ggplot2)
# this is the plot with all the points
ggplot(data = df, mapping = aes(x = x, y = y)) + geom_point()
# this is the plot with only the points for which the "binary" variable is 1
ggplot(data = subset(df, binary == 1), mapping = aes(x = x, y = y)) + geom_point()
# this is the plot with all points where they are coloured by whether "binary" is 0 or 1
ggplot(data = df, mapping = aes(x = x, y = y, colour = as.factor(binary))) + geom_point()
Something like this?
library(ggplot2)
y <- df
is.na(y) <- y == 0
ggplot(data = data.frame(x = seq_along(y), y), mapping = aes(x, y)) +
geom_point() +
scale_y_continuous(breaks = c(0, 1),
labels = c("0" = "0", "1" = "1"),
limits = c(0, 1))
It only plots points where df == 1, not the zeros. If you also want those, don't run the code line starting is.na(y).
Not sure exactly what you are asking, but here are a few options. Since your data structure is not a data frame, I've renamed it test. First, dotplot with ggplot:
library(ggplot2)
ggplot(as.data.frame(test), aes(x=test)) + geom_dotplot()
Or you could do the same thing as a bar:
qplot(test, geom="bar")
Or, a primitive base R quick look:
plot(test, pch=16, cex=3)
