how to get the values using regex in python3

Question

string = # Combinations selected:Mod Size 1024 with SHA-1(Salt len: 20); SHA-224(Salt len: 20); SHA-256(Salt len: 20); SHA-384(Salt len: 20); SHA-512(Salt len: 20);; Mod Size 2048 with SHA-1(Salt len: 20); SHA-224(Salt len: 28); SHA-256(Salt len: 32); SHA-384(Salt len: 48); SHA-512(Salt len: 64);; Mod Size 3072 with SHA-1(Salt len: 0); SHA-224(Salt len: 0); SHA-256(Salt len: 0); SHA-384(Salt len: 24); SHA-512(Salt len: 0);

I've tried so many regex but I did not get any answer

output:

{'Mod Size 1024':'SHA-1(Salt len: 20); SHA-224(Salt len: 20); SHA-256(Salt len: 20); SHA-384(Salt len: 20); SHA-512(Salt len: 20)',  
'Mod Size 2048' :'SHA-1(Salt len: 20); SHA-224(Salt len: 28); SHA-256(Salt len: 32); SHA-384(Salt len: 48); SHA-512(Salt len: 64)'}

Any suggestions?

Rakesh · Accepted Answer · 2020-06-19 11:55:16Z

3

Try using re.findall with pattern r"(Mod Size \d+) with (.*?);(;|$)"

import re

string = "# Combinations selected:Mod Size 1024 with SHA-1(Salt len: 20); SHA-224(Salt len: 20); SHA-256(Salt len: 20); SHA-384(Salt len: 20); SHA-512(Salt len: 20);; Mod Size 2048 with SHA-1(Salt len: 20); SHA-224(Salt len: 28); SHA-256(Salt len: 32); SHA-384(Salt len: 48); SHA-512(Salt len: 64);; Mod Size 3072 with SHA-1(Salt len: 0); SHA-224(Salt len: 0); SHA-256(Salt len: 0); SHA-384(Salt len: 24); SHA-512(Salt len: 0);"

for i in re.findall(r"(Mod Size \d+) with (.*?);(;|$)", string):
    print(i[:-1])

Output:

('Mod Size 1024', 'SHA-1(Salt len: 20); SHA-224(Salt len: 20); SHA-256(Salt len: 20); SHA-384(Salt len: 20); SHA-512(Salt len: 20)')
('Mod Size 2048', 'SHA-1(Salt len: 20); SHA-224(Salt len: 28); SHA-256(Salt len: 32); SHA-384(Salt len: 48); SHA-512(Salt len: 64)')
('Mod Size 3072', 'SHA-1(Salt len: 0); SHA-224(Salt len: 0); SHA-256(Salt len: 0); SHA-384(Salt len: 24); SHA-512(Salt len: 0)')

answered Jun 19, 2020 at 11:55

Rakesh

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Praveen Over a year ago

can you provide a bit of explanation to the regex.

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