I'd like to remove strings in my list.
Suppose,
x = ['feature 1' , 'feature 2' , 'feature 3' , 'feature 4']
I want to achieve,
x = [1, 2, 3, 4]
I know this can be achieved by splitting each individual element and removing the feature term and retaining the remaining value.
BUT
i want to create a common function to achieve something like this and more optimal function rather than extracting each indiviual element and doing it.. It's cumbersome.
INSTEAD
I want a solution which auto detects the strings and removes it in each element.
NOW THAT'S OPTIMAL
Please let me know below if there's anything like it.
2 Answers
This function should help you to do what you require:
import re
x = ['feature 1' , 'feature 2' , 'feature 3' , 'feature 4']
def remove_strings(x):
y = [int(re.findall('\d+', i)[0]) for i in x]
return y
remove_strings(x)
Hope this helps :)
Comments
newlist = []
def liststringtoint(list1):
for word in list1:
for letter in word:
if letter.isnumeric():
letter = int(letter)
newlist.append(letter)
1 Comment
Aditya Nikhil
Good work! But i want the resultant list to be inline without creating new list.
re.findall("\d+",str(x))I guess would probably do what you want