Checking returned data from php file with equal sign and get () method jquery

Question

I have this:

$(document).ready(function() {

$.get('getturn.php', function(data){
    if (data!=='4') { alert ('  change'); }
    if (data=='4') { alert ('no change');}
    });
});

getturn.php echoes 4 if the turn is equal to a session id, and it echoes the turn number if otherwise. The getturn.php does as it should, it echoes 4 or a number like 0,1,2,3; however when I get the data like seen above from a different file, and check if it equals to 4, I can't get the correct answer... What am I doing wrong? I thought we could check if the output was yes with data=='yes' ? but we can't check numbers with data=='4'?

please paste your php code here too? also what happens if you do console.log(data); ? — Etienne Marais
– Etienne Marais, Commented Jun 7, 2011 at 13:36
Did you check the response via firebug. may be your ajax request is cached. — DanielB
– DanielB, Commented Jun 7, 2011 at 13:37
@GaryGreen data type is a string but when i make it data='4' and data!='4' it alerts both change and no change — Arda
– Arda, Commented Jun 7, 2011 at 13:40

Community · Accepted Answer · 2017-05-23 12:04:20Z

2

Have you done an alert(data); to see what is returned?

I think you should try this slight modification:

if (data == '4') { alert ('no change');}
            else { alert ('  change'); }

Based on this answer: How do the PHP equality (== double equals) and identity (=== triple equals) comparison operators differ?

edited May 23, 2017 at 12:04

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answered Jun 7, 2011 at 13:39

Fosco

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5 Comments

Arda Over a year ago

@Frosco hmm... for somereason localhost/getturn.php echoes 4 but when i alert it it alerts 1. still the type is a string though..

Fosco Over a year ago

@Logan the first part of your response cancels out the second part. How are you sure that it echoed a 4? Unless you're using your browser dev tools and inspecting the real response how can you know?

Arda Over a year ago

@Frosco well localhost/getturn.php returns only number 4 and nothing else... isn't that enough for checking the php file? Why should it be different when I use ajax get? Could you enlighten me please?

Fosco Over a year ago

@Logan I don't know how else to explain, if alert(data) shows you 1 what does that tell you?

Arda Over a year ago

nevermind i found the problem in the php script; after it alerted 4 i did as in your answer and it worked, thanks.

ioseb · Accepted Answer · 2011-06-07 13:40:53Z

1

if understand your problem correctly, this will help:

data = parseInt(data);
if (!isNaN(data)) {
  if (data != 4) { ... }
  if (data == 4) { ... }
}

just convert "data" variable to numeric value(e.g. integer in this case)

answered Jun 7, 2011 at 13:40

ioseb

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