Fill 4 bytes little endian with python

Question

How can I convert number to 4 bytes little endian with python?

For example : 1 -> 01000000 and 258 -> 02010000

do you have any code example? or do you expect someone code it for you? please check How to Ask — dboy
– dboy, Commented Jul 1, 2020 at 21:12

Mateo Lara · Accepted Answer · 2020-07-01 21:12:56Z

4

Try with struct, 'this module performs conversions between Python values and C structs represented as Python strings':

import struct
print(struct.pack('<i', 258))

where < mean little-endian and i that the element to be pack is an integer

Output:

b'\x02\x01\x00\x00'

edited Jul 1, 2020 at 21:12

answered Jul 1, 2020 at 21:05

Mateo Lara

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2 Comments

ttx32063Eoopy.com Over a year ago

But if this code will run at 64 bits machine this will be 8 bytes. Is there any way to limit that explicit to 4 byte?

Mateo Lara Over a year ago

The code is running in a 64 bits machine and the result is as shown, if you want to know more about it please refer to: docs.python.org/2/library/struct.html @ttx32063Eoopy.com

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