To split the string values stored in array

Question

import numpy as np

import pandas as pd

a=np.array(['ma_ya','dj_kh','ja_aa'])

a1=(lambda x:x[0].split('_'),a)
a1

output:

 (<function __main__.<lambda>>, array(['ma_ya', 'dj_kh', 'ja_aa'], 
       dtype='<U5'))

i want the output to be ['ma','dj','ja'] using lambda function. kindly help

Does it need to use numpy for some reason? Otherwise a1 = map(lambda x: x.split('_')[0] , a) should work — Mustafa Quraish
– Mustafa Quraish, Commented Jul 2, 2020 at 7:42

Pramote Kuacharoen · Accepted Answer · 2020-07-02 07:43:04Z

1

a1 = list(map(lambda x: x.split('_')[0], a))

answered Jul 2, 2020 at 7:43

Pramote Kuacharoen

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Comments

James · Accepted Answer · 2020-07-02 08:36:23Z

1

As a is a np.array, you can use list comprehension

a1 = [x.split('_')[0] for x in a]

Outputs: ['ma', 'dj', 'ja']

edited Jul 2, 2020 at 8:36

answered Jul 2, 2020 at 7:44

James

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Comments

Vishal Singh · Accepted Answer · 2020-07-02 07:43:23Z

0

a1 = list(map(lambda x: x.split("_")[0], a))

print(a1)

Output:

['ma', 'dj', 'ja']

answered Jul 2, 2020 at 7:43

Vishal Singh

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Comments

ipj · Accepted Answer · 2020-07-02 07:46:13Z

0

Alternatively, use pd.Series:

a1=pd.Series(a).apply(lambda x:x.split('_')[0])

result:

0    ma
1    dj
2    ja
dtype: object

or convert to list:

a1=list(pd.Series(a).apply(lambda x:x.split('_')[0]))

output:

['ma', 'dj', 'ja']

answered Jul 2, 2020 at 7:46

ipj

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Comments

maria_g · Accepted Answer · 2020-07-02 07:47:11Z

0

Hey you can use list comprehension instead of using lambda as shown here

import numpy as np
import pandas as pd
a=np.array(['ma_ya','dj_kh','ja_aa'])
a1=[i.split('_')[0] for i in a]
print(a1)

Output : ['ma', 'dj', 'ja']

answered Jul 2, 2020 at 7:47

maria_g

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3 Comments

MrNobody33 Over a year ago

How is this different to answer?. This actually borders plagiarism.

maria_g Over a year ago

I was writing this answer and till then the same answer was already posted.I didn't check then.

MrNobody33 Over a year ago

Yes, that's true, it usually happens, but now that you realize that the answer had already been published, the best thing would be to edit it to give a different answer or delete it, otherwise it could be considered plagiarism.

DirtyBit · Accepted Answer · 2020-07-02 07:48:45Z

0

Using list-comprehension:

s = ['ma_ya','dj_kh','ja_aa']

print([x.split('_')[0] for x in s])

OUTPUT:

['ma','dj','ja']

answered Jul 2, 2020 at 7:48

DirtyBit

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1 Comment

MrNobody33 Over a year ago

How is this different to answer?. This actually borders plagiarism.

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