Sorting an Existing Map by Value in Scala

Question

I'm trying to sort a Map by value using Scala but no luck any help will be appreciable. "null value can be any order"

Input:

Map(dkd-> 2, dtes-> 3,test-> 4, dstl-> null,tsst-> null, tetd-> null ,est1-> 1)

Output

Map(est1-> 1, dkd-> 2, dtes-> 3, test-> 4, tsst-> null, dstl-> null, tetd-> null)

or

Map(est1-> 1, dkd-> 2, dtes-> 3, test-> 4, dstl-> null, tetd-> null, tsst-> null)

or

Map(est1-> 1, dkd-> 2, dtes-> 3, test-> 4, tetd-> null, dstl-> null, tsst-> null)

Maps are not sorted, especially not by value. Why do you care about the order? Is for printing? — Luis Miguel Mejía Suárez
– Luis Miguel Mejía Suárez, Commented Jul 2, 2020 at 20:16
If you need to sort a map, you are using the wrong structure, because maps are not meant to be accessed by order, they are supposed to be accessed by key — Pedro Correia Luis
– Pedro Correia Luis, Commented Jul 2, 2020 at 20:23

jwvh · Accepted Answer · 2020-07-02 20:34:26Z

3

A Map, by definition, has no order, but a List does.

Map("dkd"-> 2
  , "dstl"-> null
  , "test"-> 4
  , "tsst"-> null
  , "dtes"-> 3
  , "tetd"-> null
  , "est1"-> 1
  ).toList.sortBy{
    case (_:String,i:Int) => i
    case _ => Int.MaxValue
  }
//res0: List[(String, Any)] = 
// List((est1,1)
//    , (dkd,2)
//    , (dtes,3)
//    , (test,4)
//    , (tsst,null)
//    , (dstl,null)
//    , (tetd,null))

answered Jul 2, 2020 at 20:34

jwvh

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