I tried to print "person[0].name: a" and "person[1].name: b" and so on, based on this person array of object:
I used object entries twice, any other way I can make the loop more efficient?
const person = [{
name: 'a',
}, {
name: 'b'
}]
Object.entries(person).forEach(([key, value]) => {
Object.entries(value).forEach(([key2, value2]) => {
console.log(`person[${key}].${key2}`, ':', value2)
})
})You could take a recursive approach and hand over the parent path.
const
show = (object, parent) => {
const wrap = Array.isArray(object) ? v => `[${v}]` : v => `.${v}`;
Object.entries(object).forEach(([k, v]) => {
if (v && typeof v === 'object') show(v, parent + wrap(k));
else console.log(parent + wrap(k), v);
});
},
person = [{ name: 'a' }, { name: 'b' }];
show(person, 'person');You don't really need the first call. person is already an Array.
const person = [{
name: 'a',
}, {
name: 'b'
}]
person.forEach((value, key) => {
Object.entries(value).forEach(([key2, value2]) => {
console.log(`person[${key}].${key2}`, ':', value2)
})
})Just in case forEach is for side effects. If you want to create another array with transformed values you better use map/flatMap instead.
const person = [{
name: 'a',
}, {
name: 'b'
}]
const transformed = person.flatMap((value, key) => {
return Object.entries(value).map(([key2, value2]) => `person[${key}].${key2}:${value2}`)
})
console.log(transformed)You can also try something like this, with only one forEach() loop
const person = [{
name: 'a',
},{
name: 'b'
}];
person.forEach((el,i) => {
let prop = Object.keys(el).toString();
console.log(`person[${i}].${prop}`, ':', el[prop])
});
['a', 'b'])?