for example look at this array, I want to remove those objects which the the value of their "age" is the same.
var array =[
{age:21,name:"sam",class="C"},
{age:24,name:"david",class="f"},
{age:45,name:"zack",class="f"},
{age:21,name:"jeff",class="g"},
{age:21,name:"marco",class="a"},
{age:26,name:"john",class="d"},
];
I want to get this result:
[
{age:21,name:"sam",class="C"},
{age:24,name:"david",class="f"},
{age:45,name:"zack",class="f"},
{age:26,name:"john",class="d"},
];
You can use reduce
var array = [
{age:21,name:"sam",class:"C"},
{age:24,name:"david",class:"f"},
{age:45,name:"zack",class:"f"},
{age:21,name:"jeff",class:"g"},
{age:21,name:"marco",class:"a"},
{age:26,name:"john",class:"d"}
];
let result = array.reduce((a,v) => {
let i = a.findIndex(person => person.age === v.age);
if(i !== -1){
return a;
}
return [...a, {...v}];
},[]);
console.log(result);You can do this
var array =[
{age:21,name:"sam",class:"C"},
{age:24,name:"david",class:"f"},
{age:45,name:"zack",class:"f"},
{age:21,name:"jeff",class:"g"},
{age:21,name:"marco",class:"a"},
{age:26,name:"john",class:"d"},
];
var res = array.filter((i, index, self) => self.findIndex(k => k.age === i.age)==index);
console.log(res);
//Another clever way with lesser complexity :)
var res = array.reduce((a,v)=>{
if(!a[v.age]){
a[v.age] = v
};
return a
},{})
console.log(Object.values(res))