How to run this java class in command line in windows?

Question

package com.test01;

public class test01 {
    public static void main(String[] args)
    {
        System.out.println("hi");
    }
}

I think the java application launcher is very stupid. I have point out the test01.class position:
java -cp . test01(.class)
but this doesn't works. It's very hard to use.

the -cp have to point out the dir which contain 'com'..... so, this works: java -cp ./bin/(contain com) com.test01.test01 — lovespring
– lovespring, Commented Jun 11, 2011 at 7:29

Jon Skeet · Accepted Answer · 2011-06-11 07:39:58Z

20

You would run

java com.test01.test01

but having a class with the same name as a package is a really bad idea (as well as not following the Java naming conventions).

You'd need to run it with the relevant class on the classpath. For example, you could just compile it like this (from the "root" of your source tree):

javac -d . [path to source file]
java com.test01.test01

or if you've got your source organized appropriately already:

javac com\test01\test01.java
java com.test01.test01

edited Jun 11, 2011 at 7:39

answered Jun 11, 2011 at 7:15

Jon Skeet

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3 Comments

Erich Kitzmueller Over a year ago

OK, now that you have included the compiling part, I've deleted my answer for redundancy.

Kieveli Over a year ago

What if I have a lib folder and out folders?

Jon Skeet Over a year ago

@Kieveli: It's not clear what you mean. I suggest you ask a new, detailed question.

Sajan Franco · Accepted Answer · 2013-08-05 15:58:08Z

3

You should be changing over to the base directory from where the classes start

java -cp $CLASSPATH:.: com.test01.test01

But naming a class "test01" is not a good naming convention.

answered Aug 5, 2013 at 15:58

Sajan Franco

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