How condition can be executed without breaking the loop in python

Question

I tried to iterate over a list again and again but when the first round is finished I have to print dashes. But the dashes are printing before the round gets fully finished. Here is what I tried so far:

from time import sleep as p

lit = [1, 2, 3, 4, 5]
n = 0
while True:
    p(1)
    print(lit[n])
    n = (n+1) % len(lit)
    if lit[n] == lit[-1]:
        print('-'*80)

I also tried the following condition too but it didn't work

if n == len(lit):
    print('-'*80)

here is what I'm getting

1
2
3
4
--------------------------------------------------------------------------------
5
1
.

here is an expected output

1
2
3
4
5
--------------------------------------------------------------------------------
1
.

If you print the dashes before increasing n, you'll yield the desired output. Alternatively, testing for n == 0 after incrementing would work as well — Ronald
– Ronald, Commented Aug 6, 2020 at 12:38
A less wacky approach perhaps? while True: for x in lit: print(x); print dashes; sleep if you really have to — tripleee
– tripleee, Commented Aug 6, 2020 at 12:43

Scott Hunter · Accepted Answer · 2020-08-06 12:38:40Z

4

The proper test would be n == 0.

answered Aug 6, 2020 at 12:38

Scott Hunter

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Comments

drops · Accepted Answer · 2020-08-06 12:40:16Z

2

Update your n after the print:

from time import sleep as p

lit = [1, 2, 3, 4, 5]
n = 0
while True:
    p(1)
    print(lit[n])
    if lit[n] == lit[-1]:
        print('-'*80)
    n = (n+1) % len(lit)

Output:

1
2
3
4
5
----------------

answered Aug 6, 2020 at 12:40

drops

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Comments

alec_djinn · Accepted Answer · 2020-08-06 12:47:02Z

1

I am not sure if I got the question correctly. Isn't this enough?

from time import sleep as p

lit = [1, 2, 3, 4, 5]
while True:
    for n in lit:
        p(1)
        print(n)
    print('-'*80)

answered Aug 6, 2020 at 12:47

alec_djinn

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Comments

chirag aggarwal · Accepted Answer · 2020-08-06 13:01:41Z

1

I think this should work for you,

from time import sleep as p

lit = [1, 2, 3, 4, 5]
n = 0
while True:
    p(1)
    print(lit[n])
    n = (n+1) % len(lit)
    if lit[n-1] == lit[-1]:
        print('-'*80)

answered Aug 6, 2020 at 13:01

chirag aggarwal

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Comments

Jannes Carpentier · Accepted Answer · 2020-08-06 12:48:14Z

0

Make sure you do things in the correct order

First print the number
Then if the number is the last element, print the line
Finally increment the number

Your code but rearranged:

from time import sleep as p

lit = [1, 2, 3, 4, 5]
n = 0
while True:
    p(1)
    print(lit[n])
    if lit[n] == lit[-1]:
        print('-'*80)
    n = (n+1) % len(lit)

edited Aug 6, 2020 at 12:48

answered Aug 6, 2020 at 12:38

Jannes Carpentier

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