Passing a single row in a 3D array to function

Question

I am trying to pass a row of a multidimensional array to a function as pointer. The 3d arrays are stores inside the following structure.

typedef struct{
double complex CUR[MAX_CHANNELS][MAX_HARM][4];
double complex VOL[MAX_CHANNELS][MAX_HARM][4];
}VALS;

I am trying to pass one row into the following function as a parameter.

void foo(double complex *V,double complex *I);

In the main program I am passing the first row as a pointer. But in the execution I am getting an "incompatible pointer type warning".

foo(&VALS.VOL[2][0],&VALS.CUR[2][0]);

You don't need &. Arrays automatically decay to pointers when used as function arguments. — Barmar
– Barmar, Commented Aug 7, 2020 at 0:15

LeMoonStar · Accepted Answer · 2020-08-07 10:31:28Z

1

Since the third dimension is still an array, the resulting type of vals.VOL[2][0] and vals.CUR[2][0] is of type double* (pointing to the first element of the array). therefore a & is not needed:

foo(vals.VOL[2][0], vals.CUR[2][0]);

answered Aug 7, 2020 at 10:31

LeMoonStar

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