Python - TypeError: an integer is required (got type datetime.datetime)

Question

I have the following code:

import datetime
from datetime import datetime as dt

def ceil_dt(dt, delta):
    return dt + (dt.min - dt) % delta

NextInterval5m = ceil_dt(now, timedelta(minutes=5))

unixtime5m = dt.fromtimestamp(NextInterval5m)

The problem is that i keep getting the following error:

TypeError: an integer is required (got type datetime.datetime)

Can someone help me out on this? I don't understand to what i am supposed to convert NextInterval5m in order to make it work. I'm trying to convert NextInterval5m to an Unix timestamp

What is ceil_dt?

Axiumin_
– Axiumin_

2020-08-08 22:30:29 +00:00
Commented Aug 8, 2020 at 22:30 — Axiumin_
– Axiumin_, Commented Aug 8, 2020 at 22:30
My bad, it's a function that i forgot to include

JayK23
– JayK23

2020-08-08 22:31:17 +00:00
Commented Aug 8, 2020 at 22:31 — JayK23
– JayK23, Commented Aug 8, 2020 at 22:31

Axiumin_ · Accepted Answer · 2020-08-08 22:35:54Z

2

You should be able to convert it into a unix timestamp by using .timestamp() on a datetime.datetime object. However, this function is exclusive to Python 3. If you need something for python 2, you can use .total_seconds() which requires a datetime.time_delta object instead.

Documentation: https://docs.python.org/3.8/library/datetime.html#datetime.datetime.timestamp

answered Aug 8, 2020 at 22:35

Axiumin_

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bigbounty · Accepted Answer · 2020-08-08 22:36:25Z

1

If you are using python 3.3+, use .timestamp()

import datetime
from datetime import datetime as dt
from datetime import timedelta

def ceil_dt(dt, delta):
    return dt + (dt.min - dt) % delta

now = dt.now()
NextInterval5m = ceil_dt(now, timedelta(minutes=5))
unixtime5m = NextInterval5m.timestamp()
print(unixtime5m)

Output:

1596926400.0

OR

import datetime
from datetime import datetime as dt
from datetime import timedelta

def ceil_dt(dt, delta):
    return dt + (dt.min - dt) % delta

now = dt.now()
NextInterval5m = ceil_dt(now, timedelta(minutes=5))
unixtime5m = NextInterval5m.timestamp()

print((NextInterval5m - datetime.datetime(1970,1,1)).total_seconds())

answered Aug 8, 2020 at 22:36

bigbounty

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