What is the python equivalent of curl -x

Question

What is the -x option in curl and how to implement equivalent command in python using the requests library. I want the following command to be in python.

curl \
  -X DELETE \
  -H "Accept: application/vnd.github.v3+json" \
  https://api.github.com/repos/octocat/hello-world

MukeshRKrish · Accepted Answer · 2020-08-10 06:32:20Z

1

import requests

headers = {'Accept': 'application/vnd.github.v3+json'}

response = requests.delete(url='https://api.github.com/repos/octocat/hello-world', headers=headers)

-X DELETE is the HTTP method you are using, here we use delete method from requests module

-H is to specify the request headers, here we achieve it with headers parameter

answered Aug 10, 2020 at 6:32

MukeshRKrish

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michjnich · Accepted Answer · 2020-08-10 06:51:45Z

0

I believe this would be:

import requests

headers = {
    'Accept': 'application/vnd.github.v3+json',
}

response = requests.delete('https://api.github.com/repos/octocat/hello-world', headers=headers)

Another alternative would be to use PycURL, which provides the setopt option:

crl = pycurl.Curl()
crl.setopt(crl.URL, "<url here>")
crl.setopt(crl.CUSTOMREQUEST, "DELETE")

answered Aug 10, 2020 at 6:51

michjnich

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