How do I split on multiple conditions in string? (JavaScript)

Question

How do I get given value?

name // google
index // 0
LastName //Last Name

My approach is not working because I have a singular condition '.'

value = '#[pill(google.0.LastName)]'
const [name, index, name] = value.split('.')

Regex is /#\[pill\((.*?)\)\]/gi

can you provide an example in the answer? I added Regex pattern — merry-go-round
– merry-go-round, Commented Aug 12, 2020 at 18:47

Taplar · Accepted Answer · 2020-08-12 18:51:39Z

2

var test = '#[pill(google.0.LastName)]';

console.log(
  test.substring(test.indexOf('(') + 1, test.indexOf(')')).split('.')
);

console.log(
  test.match(/\(([^)]+)\)/)[1].split('.')
);

Here are a couple different ways; one with substring and one with a regexp.

answered Aug 12, 2020 at 18:51

Taplar

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Comments

Jack · Accepted Answer · 2020-08-12 18:57:40Z

1

You can forgo the split using three matching expressions in your regex like this , #\[pill\((.*)\.(.*)\.(.*)\)\]

var string = "#[pill(google.0.LastName)]"
var [_, name, Index, LastName] = string.match(/#\[pill\((.*)\.(.*)\.(.*)\)\]/)

console.log(name, Index, LastName)

edited Aug 12, 2020 at 18:57

answered Aug 12, 2020 at 18:50

Jack

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1 Comment

merry-go-round Over a year ago

can you provide a working example? It doesn't work on my end

Nina Scholz · Accepted Answer · 2020-08-12 18:52:57Z

1

You could split the parts of the matched string.

const
    string = '#[pill(google.0.LastName)]',
    [firstName, index, lastName] = string.match(/[^\(]+(?=\))/)[0].split('.');
    

console.log(firstName);
console.log(index);
console.log(lastName);

answered Aug 12, 2020 at 18:52

Nina Scholz

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