Problem Notice: Trying to access array offset on value of type null in [duplicate]

Question

What does the error mean and how do I fix it?

( Notice: Trying to access array offset on value of type null in....)

public function hasPermission($key)
{
    $group = $this->_db->get('groups', array('id', '=', $this->data()->group));
    if ($group->count()) {
        $permissions = json_decode($group->firstResult()->permissions, true);

        if ($permissions[$key] == true) {
            return true;
        }
    }

    return false;
}

The error is on this line:

if ($permissions[$key] == true) {

Regards

This question is already answered, example at stackoverflow.com/questions/59336951/…. — Tony Stark
– Tony Stark, Commented Aug 16, 2020 at 16:16
Are you sure the value for $key is available in the array? — Dupinder Singh
– Dupinder Singh, Commented Aug 16, 2020 at 16:25

Ankit Jindal · Accepted Answer · 2020-08-16 16:34:06Z

1

You don't need to do

if ($permissions[$key] == true) {
     return true;
}

Rather try this:

if (isset($permissions[$key]) && $permissions[$key]) {
    return true;
}

Hope this works!!

answered Aug 16, 2020 at 16:34

Ankit Jindal

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Comments

Thomas Wijnands · Accepted Answer · 2020-08-16 16:22:32Z

-1

It means that you're trying to get data from you're array while the parameter returns NULL in $permissions[$key]. So check if you're $key has any value.

answered Aug 16, 2020 at 16:22

Thomas Wijnands

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