I am using this in Python 3.6:
filetest="test.txt"
with open(filetest,"r") as file:
How should I make Python console to display "File not available" as an output if no input on the filetest is detected? (such as there is no test.txt in the directory)
You can just wrap it in a try-except block, and if there is no file named "test.txt" then you will print the message: "File not available".
A simple example is:
filename="test.txt"
try:
with open(filetest,"r") as file:
pass
except OSError as e:
print("File not available")
print(e.strerror)
I added the OSError because it indicate problem in file handling where you can read about in the following link: https://docs.python.org/3/library/exceptions.html
One can also use the FileNotFoundError exception.
with block (even just a pass if you don't need to use the file) to make this syntactically legal.
except clause ... here you’ll happily catch all sorts of other errors in the with block
OSError exception and added a link for the user to read about built-in exceptions
except OSError as e: and then print(e.strerror) so that you don't mask a different problem with an assumed no-such-file.use try-except a simple sample has given below:
filename = 'test.txt'
try:
with open(filename,"r") as file:
read_file = file.read()
except FileNotFoundError:
print("File not found")
Try-except blocks are what you look for.
try:
filename=test.txt
with open(filetest,"r") as file:
print('File is available')
except EnvironmentError: # any IOError or OSError will be captured
print('File not available')
try/exceptblock or check the presence of the file before hand usingosorpathmoduleFileNotFoundErrorif the file you want to read is not exists. Catch a bare exception is not a good habit for all programming language.'test.txt'is a string with a file name,test.txtis the attributetxtof the objecttest.