Append bash script content to another file

Question

This is my bash script

#!/bin/bash

filenames="root/simulate/*.txt"
for f in "$filenames"; do
#append "#" to all .txt files
 sed -i -e 's/^/#/' $filenames
#append content of this bash script to all .txt files
 cat "$0" >> "$f"
done

But instead of appending its bash script content to all existing ".txt" files, it creates a new "*.txt" file in the directory and adds the content of the other ".txt" files into it, and then appends the bash script to that new file. Can anybody help? Thank you

Why are you running sed on $filenames every time through the loop, instead of $f? — Barmar
– Barmar, Commented Aug 25, 2020 at 14:50

Ivan · Accepted Answer · 2020-08-26 05:59:09Z

1

That is because * not expanding inside "", try it like this:

#!/bin/bash
for f in root/simulate/*.txt; do
    #append "#" to all .txt files
    sed -i -e 's/^/#/' "$f"
    #append content of this bash script to all .txt files
    cat "$0" >> "$f"
done

And you don't need a loop here, just this sed command:

#!/bin/bash
sed -i 's/^/#/;$r'"$0" root/simulate/*.txt

edited Aug 26, 2020 at 5:59

answered Aug 25, 2020 at 14:37

Ivan

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Comments

fr4gm3nt · Accepted Answer · 2020-08-25 14:43:12Z

0

If You want to use variable try

for f in $filenames; do

answered Aug 25, 2020 at 14:43

fr4gm3nt

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