How to access a method variable (Tkinter) from another method in same class?

Question

I have defined some variables in method 1 and i call method 2 from it. In method 2, i have to access method 1 variable.

class Window(Frame):

    def __init__(self, master=None):
        Frame.__init__(self, master)               
        self.master = master
        self.myElements()

    def myElements(self):
        self.master.title("1841144-SANDRINE P JOY")
        self.pack(fill=BOTH , expand=1)
        label1=Label(text="Starts with").place(x=10,y=0)
        generateButton = Button(self,text="Generate", command=self.autogen)
        generateButton.place(x=150,y=0)
        label2=Label(text="--Here , your Random Name appears--").place(x=70,y=30)

    def autogen(self):
        randomName=pick(names)
        label2.insert(INSERT,randomName) #This line is wrong

Thanks @AKX & @Cool Cloud for figuring my errors

Here is the corrected code

creating an instance of a method of the variable was all needed for it

def __init__(self, master=None):
        Frame.__init__(self, master)               
        self.master = master
        self.myElements()

    def myElements(self):
        self.master.title("1841144-SANDRINE P JOY")
        self.pack(fill=BOTH , expand=1)
        label1=Label(text="Starts with").place(x=10,y=0)
        generateButton = Button(self,text="Generate", command=self.autogen)
        generateButton.place(x=150,y=0)
        self.result=Text(self,width=10,height=1)
        self.result.place(x=70,y=30)
        mstart = Label(self, text="Starting with M",bg='white',fg='black',font=("italic", 10)).place(x=20,y=50)
        mtext = Text(self, width=15, height=10)
        mtext.place(x=10,y=70)

        pstart = Label(self, text="Starting with P",bg='white',fg='black',font=("italic", 10)).place(x=140,y=50)
        ptext = Text(self, width=15, height=10)
        ptext.place(x=120,y=70)

        nstart = Label(self, text="Starting with N",bg='white',fg='black',font=("italic", 10)).place(x=260,y=50)
        ntext = Text(self, width=15, height=10)
        ntext.place(x=240,y=70)     

    def autogen(self):
        randomName=pick(names)
        self.result.insert(INSERT,randomName)

The variable label2 ceases to exist as soon as myElements() returns. autogen() cannot possibly access it, because there's nothing to access. Store it as an instance attribute, instead. — jasonharper
– jasonharper, Commented Sep 5, 2020 at 18:03
@jasonharper wouldnt saying self.label2=Label(...) and then self.label2.insert(...) work? — Delrius Euphoria
– Delrius Euphoria, Commented Sep 5, 2020 at 18:10
@SandrinJoy You have to say self.label2 = Label(...) then self.label2.place(..) then say self.label2.insert(..) but i believe Label does not have insert() method — Delrius Euphoria
– Delrius Euphoria, Commented Sep 5, 2020 at 18:33

AKX · Accepted Answer · 2020-09-05 18:35:40Z

1

Store them as instance variables (self.label1 etc.):

class Window(Frame):
    def __init__(self, master=None):
        Frame.__init__(self, master)
        self.master = master
        self.myElements()

    def myElements(self):
        self.master.title("1841144-SANDRINE P JOY")
        self.pack(fill=BOTH, expand=1)
        self.label1 = Label(text="Starts with")
        self.label1.place(x=10, y=0)
        self.generateButton = Button(self, text="Generate", command=self.autogen)
        self.generateButton.place(x=150, y=0)
        self.label2 = Label(text="--Here , your Random Name appears--")
        self.label2.place(x=70, y=30)

    def autogen(self):
        randomName = pick(names)
        self.label2.insert(INSERT, randomName)

edited Sep 5, 2020 at 18:35

answered Sep 5, 2020 at 18:03

AKX

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8 Comments

acw1668 Over a year ago

self.label2 is None as it is the result of Label(...).place(...).

Sandrin Joy Over a year ago

return self.func(*args) File "nameGen.py", line 43, in autogen self.label2.insert(INSERT,randomName) AttributeError: 'NoneType' object has no attribute 'insert'

Sandrin Joy Over a year ago

@acw1668 yes , its NoneType

Delrius Euphoria Over a year ago

@AKX i still expect an error because i believe Label dont have insert() method

Sandrin Joy Over a year ago

Thanks a lot guys , i fixed it. It was that label error

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