Python3 filter/remove strings of a list

Question

i grabed some data and stuff with my crawler and now i have to analyse them.

I got a list with different links of some pictures, but i just want to save the ones without "/Thumbnails"

pictures = ['Media/Shop/922180cruv.jpg', 'Media/Shop/922180cruvdet.jpg', 'Media/Shop/Thumbnails/922180cruvx320x240.jpg', 'Media/Shop/Thumbnails/922180cruvdetx320x240.jpg']

Is there a way to say "if string got /Thumbnails", remove all from the list?. I got a csv with ~25000 list in separate columns.

Already tried with remove() and indexing, but my lists are different, so the index for the first list wont fit to the second list for example

pictures = [path in pictures if "/Thumbnails/" not in path]? — L3viathan
– L3viathan, Commented Sep 9, 2020 at 10:13

Andrej Kesely · Accepted Answer · 2020-09-09 10:16:56Z

1

Use filtering list comprehension:

pictures = ['Media/Shop/922180cruv.jpg', 'Media/Shop/922180cruvdet.jpg', 'Media/Shop/Thumbnails/922180cruvx320x240.jpg', 'Media/Shop/Thumbnails/922180cruvdetx320x240.jpg']

pictures = [p for p in pictures if not "/Thumbnails/" in p]

print(pictures)

Prints:

['Media/Shop/922180cruv.jpg', 'Media/Shop/922180cruvdet.jpg']

answered Sep 9, 2020 at 10:16

Andrej Kesely

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Anuj Jindal · Accepted Answer · 2020-09-09 10:16:06Z

0

You can user split and join feature of python as below.

pictures = ['Media/Shop/922180cruv.jpg', 'Media/Shop/922180cruvdet.jpg', 
            'Media/Shop/Thumbnails/922180cruvx320x240.jpg', 
            'Media/Shop/Thumbnails/922180cruvdetx320x240.jpg']
pictures2= []
for pic in pictures:
  if "Thumbnails" in pic:
    pic_list = pic.split("Thumbnails/")
    pic = "".join(pic_list) 
    print(pic)
    pictures2.append(pic)
  else:
    pictures2.append(pic)
print(pictures2)

output

['Media/Shop/922180cruv.jpg', 'Media/Shop/922180cruvdet.jpg', 'Media/Shop/922180cruvx320x240.jpg', 'Media/Shop/922180cruvdetx320x240.jpg']

answered Sep 9, 2020 at 10:16

Anuj Jindal

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1 Comment

kekw Over a year ago

your solution only deletes the "/Thumbnails" part, that is not what i asked for, but i appreciate your effort kind sir!

Sumak · Accepted Answer · 2020-09-09 10:34:33Z

0

You can iterate through the list and check if each string contains the substring /Thumbnail

result   = []
pictures = ['Media/Shop/922180cruv.jpg', 'Media/Shop/922180cruvdet.jpg', 
            'Media/Shop/Thumbnails/922180cruvx320x240.jpg', 
            'Media/Shop/Thumbnails/922180cruvdetx320x240.jpg']


for picture in pictures:
    if picture.find('/Thumbnails') == -1:
        result.append(picture)

Output:

['Media/Shop/922180cruv.jpg', 'Media/Shop/922180cruvdet.jpg']

Demo: https://onlinegdb.com/rkAo1EL4w

edited Sep 9, 2020 at 10:34

answered Sep 9, 2020 at 10:27

Sumak

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