Convert string with hard coded line breaks into matrix in python

Question

I am trying to create a class that takes a string of digits with hard coded line breaks and outputs a matrix and details about that matrix. In the first instance i just want to be able to create the matrix but I am struggling. I'm aware that I could probably do this very easily with numpy or something similar but trying to practice.

class Matrix:
def __init__(self, matrix_string):
    self.convert_to_list = [int(s) for s in str.split(matrix_string) if s.isdigit()]
    self.split = matrix_string.splitlines()

I think i want to combine the two things I have already done but I cant figure out how to apply my convert_to_list method to every element in my split method.

Getting very confused.

SAMPLE INPUT/OUTPUT

Input = " 1 8 7 /n 6 18 2 /n 1 9 7 "

Desired Output = [[1, 8, 7], [6, 18, 2], [1, 9, 7]]

Mike67 · Accepted Answer · 2020-09-19 15:55:54Z

1

It looks like you want a list of lists. For that you can use nested list comprehension.

s = " 1 8 7 /n 6 18 2 /n 1 9 7 "
lst = [[int(x) for x in r.split()] for r in s.split('/n')]
print(lst)

Output

[[1, 8, 7], [6, 18, 2], [1, 9, 7]]

answered Sep 19, 2020 at 15:55

Mike67

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1 Comment

Will Gosnold Over a year ago

That's great, thank you, yes i was struggling with the logic of that extra for loop. Really helpful, thank you.

jameel saeb · Accepted Answer · 2020-09-19 16:19:30Z

0

It's not that hard actually:

s = " 1 8 7 /n 6 18 2 /n 1 9 7 "
print([i.split() for i in s.split('/n')])

easier way but longer:

s = s.split('/n')
new = []
for i in s:
    new.append(i.split())
print(new)

output:

[['1', '8', '7'], ['6', '18', '2'], ['1', '9', '7']]

edited Sep 19, 2020 at 16:19

answered Sep 19, 2020 at 16:06

jameel saeb

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