I have a list dictionary like this: {1: {'a': 5, 'score': 3}, 2: {'a': 6, 'score': 1}, 3: {'a': 7, 'score': 2}} and want to sort it using its score attribute.
Intended output: {2: {'a': 6, 'score': 1}, 3: {'a': 7, 'score': 2}, 1: {'a': 5, 'score': 3}}
I have trying to use the built-in function to sort the list but its not giving desired output
updatedList = sorted(b, key=lambda k: k['score'])
Any hints how I can get the desired output?
Your data structure is a nested dictionary, not a list.
To sort the dictionary, you can modify your key function to this:
>>> d = {1: {'a': 5, 'score': 3}, 2: {'a': 6, 'score': 1}, 3: {'a': 7, 'score': 2}}
>>> dict(sorted(d.items(), key=lambda x: x[1]['score']))
{2: {'a': 6, 'score': 1}, 3: {'a': 7, 'score': 2}, 1: {'a': 5, 'score': 3}}
Which converts the original dictionary to dict.items, then uses the score key from the dictionary in the (key, value) tuple. Then after sorting with sorted(), we can convert back to a dictionary with dict().
This works in Python 3.6+ since dictionaries are ordered. If you are using a lower python version, you can maintain dictionary insertion order with collections.OrderedDict instead.
For sorting a Nested Dictionary use the key argument for sorted(). It lets you specify a function that, given the actual item being sorted, returns a value that should be sorted by.
N_Dictionary = {1: {'a': 5, 'score': 3}, 2: {'a': 6, 'score': 1}, 3: {'a': 7, 'score': 2}}
s_values = sorted(N_Dictionary.items(), key = lambda x: x[1]["score"] )
s_values
