how to pass additional argument along with *args in Python

Question

I have a function that takes *arg and an additional positional argument. but when calling this function I am getting below error. Any help how to pass this additional argument

**error**:
export_bundle() missing 1 required keyword-only argument: 'dict'

from stix2 import MemoryStore, Identity
import datetime

timestamp = datetime.datetime.today().strftime('%Y-%m-%d-%H:%M:%S')

id1 = Identity(
    name="John Smith",
    identity_class="individual",
    description="Just some guy",
)
id2 = Identity(
    name="John Smith",
    identity_class="individual",
    description="A person",
)

dict= {"id":1234, "name":"abd"}

def export_bundle(self, *args, dict):
   mem = MemoryStore()
   for sdo in args:
      mem.add([sdo])
   mem.save_to_file(self.output_location + str(dict['id']) + timestamp+ '.json')
    del mem

export_bundle(id1, id2, dict)

Read the error message carefully: missing a keyword-only argument. — wim
– wim, Commented Sep 28, 2020 at 4:00
You can't define a function that takes positional arguments after *args. — user2357112
– user2357112, Commented Sep 28, 2020 at 4:11

VietHTran · Accepted Answer · 2020-09-28 12:22:58Z

3

You declared the function export_bundle with variable number of arguments (*args), so if you want to define the dict argument at the end it needs to be keyword-only parameter (dict). You can call it as export_bundle(id1, id2, dict=dict) if you want to pass a value for dict.

def export_bundle(self, *args, dict):
   mem = MemoryStore()
   for sdo in args:
      mem.add([sdo])
   mem.save_to_file(self.output_location + str(dict['id']) + timestamp+ '.json')
   del mem

export_bundle(id1, id2, dict=dict)

edited Sep 28, 2020 at 12:22

answered Sep 28, 2020 at 4:14

VietHTran

2,3282 gold badges11 silver badges16 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

user2357112 Over a year ago

Adding =None in the function definition does not make the argument keyword-only. Putting it after a * argument is what makes it keyword-only. =None in the definition gives the argument a default value, which is a completely unrelated thing.

user2357112 Over a year ago

thing=whatever in a function call passes an argument by keyword. thing=whatever in a function definition gives the argument a default value. These two things are 100% unrelated, but happen to use confusingly similar syntax.

VietHTran Over a year ago

@user2357112supportsMonica You're right. I just tested it and it seems to be the case. I've removed the =None for minimizing changes from OP's code

st_bones Over a year ago

I am getting below error as well when I called the function as you have suggested: 'dict' object has no attribute 'output_location' . There must be some way to pass self argument

Vger Over a year ago

@st_bones The error you're getting doesn't seem to be related to your previous error. It's because you're accessing the property output_location of self parameter, in this case id1, which doesn't exist in Identity object. docs.oasis-open.org/cti/stix/v2.1/cs01/…

Jeevan Chaitanya · Accepted Answer · 2020-09-28 04:15:30Z

0

Always function parameters first & then *args, **kwargs

def export_bundle(self, dictm,*args):
   mem = MemoryStore()
   for sdo in args:
      mem.add([sdo])
   mem.save_to_file(self.output_location + str(dict['id']) + timestamp+ '.json')
    del mem```

answered Sep 28, 2020 at 4:15

Jeevan Chaitanya

1,38411 silver badges12 bronze badges

1 Comment

st_bones Over a year ago

I am getting below error when I called the function as you have suggested: 'dict' object has no attribute 'output_location' . There must be some way to pass self argument?

Collectives™ on Stack Overflow

how to pass additional argument along with *args in Python

2 Answers 2

5 Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

5 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related