Find if a string from an array is included on another string from the same array

Question

I count with the following example array

let animals = ['dog', 'cat', 'egypt cat', 'fish', 'golden fish']

the basic idea is get to the following result removing the elements which are included on the other strings

['dog', 'egypt cat', 'golden fish']

My approach was detect which are included iterating twice on the array and comparing the values

let arr2 = []
arr.forEach((el, i) => {
    arr.forEach((sub_el, z) => {
        if (i != z && sub_el.includes(el)) {
          arr2.push(el)
        }
      })
    })

then filter the array with those matched values. Anyone has a simplest solution?

Does this answer your question? Remove occurrences of duplicate words in a string — Uzair Warsi
– Uzair Warsi, Commented Sep 28, 2020 at 14:36
For your animals example input, do you want to remove all values from it? — CertainPerformance
– CertainPerformance, Commented Sep 28, 2020 at 14:38

Nina Scholz · Accepted Answer · 2020-09-28 14:44:53Z

1

You need to itterate the array again and then check any string.

This approach minimizes the iteration by a short circuit on found of a matching string.

let animals = ['dog', 'cat', 'egypt cat', 'fish', 'golden fish'],
    result = animals.filter((s, i, a) => !a.some((t, j) => i !== j && t.includes(s)));

console.log(result);

edited Sep 28, 2020 at 14:44

answered Sep 28, 2020 at 14:39

Nina Scholz

388k26 gold badges367 silver badges417 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Find if a string from an array is included on another string from the same array

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related